Zorch
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Joined: 3/7/2010 Status: offline

From https://en.wikipedia.org/wiki/Enigma_machine Mathematical analysis The Enigma transformation for each letter can be specified mathematically as a product of permutations.[18] Assuming a threerotor German Army/Air Force Enigma, let P denote the plugboard transformation, U denote that of the reflector, and L, M, R denote those of the left, middle and right rotors respectively. Then the encryption E can be expressed as Combining three rotors from a set of five, each of the 3 rotor settings with 26 positions, and the plugboard with ten pairs of letters connected, the military Enigma has 158,962,555,217,826,360,000 different settings (nearly 159 quintillion or about 67 bits).[19] Note that (5x4x3) x (26^3) x [26! / (6! x 10! x 2^10)] = 158,962,555,217,826,360,000 ≈ 267.1
