obrien979
Posts: 27
Joined: 5/18/2018 Status: offline

quote:
ORIGINAL: Dragon029 Radar signature is measured in dBsm, which is a decibel / logarithmic scale. To convert from decibel square metres to normal square metres, you use the formula: area in square metre = 10 ^ (dBsm / 10) Then to convert an area in square metres back into dBsm, you use the formula (where the log is using base 10): area in dBsm = 10 x log(area in square metres) Due to the nature of logarithms and powers, the more negative a value is in dBsm, the smaller an area it represents. So according to that chart (which is going to be speculation or from an incomplete simulation keep in mind), the F117A has an average radar signature of 14dBsm in radar bands AD, which roughly equals 0.04m^2, and a radar signature of 24dBsm in radar bands EM, which roughly equals 0.004m^2. The F22 meanwhile apparently has an average radar signature in the AD bands of 20dBsm or 0.01m^2 (4x smaller than the F117), and an average radar signature in the EM bands of 30dBsm or 0.001m^2 (again 4x smaller than the F117). Thank you for this outstanding explanation in Layman's terms. I think I have an understanding of this now. I suspected that the lower the negative value, the better its stealthiness. Time to put this new knowledge to test on some missions.
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v/r, Brandon O'Brien
