I so agree, and just imagine a 7 day continous bombardment of a 25-mile front with over 1,5 million shells of various calibers, that should annihilate everything, nobody could survive this, and those few that will should be too shell shocked as to offer any resistance whatsoever! You should be able to advance without any resistance over that part of the front after such a massive bombardment, right?
1.) About a million of that 1.5 million shells were 18 pounder shrapnel shells, only about 0.5 million was HE, again, fired mainly from light guns. John Keegan in his analysis in "Face of Battle" estimates that only about 900 tons of HE were actually delivered in the preliminary bombardment.
2.) Dividing that 900 tons by seven days gives us a mere HE weight of 128.5 tons a day.
A carpet bomb attack by heavy bombers is going to deliver quite a lot of HE in about an hour or so.
It really is quite easy to miss with bombs dropped from high altitude.
Even with radar computing bombsights? The B-36's K-1 bomb/nav system could bomb at night from high altitudes (40,000+ feet) with better accuracy than former daylight bombing at much lower altitudes.
If you think this is impossible, look at the last raids of WWII by B-29s against the Shimotsuma oil refinery. Bombing by night, 78% of the bombs fell within 1,000 feet of the aimpoint.
So with 30 bombers this is an area of 7.5*7.2 kilometres, for a total of 54 square kilometres. Let's be generous and figure each of the 216 bombs dropped is deadly over an area of 25 square metres (since folks are going to be mostly lying in dips in the ground, behind trees, etc). This gives us a figure of 5,400 square metres, or 5.4 square kilometres. 10% of the area bombed. That's presuming that the defenders haven't dug holes for themselves in advance.
1.) 30 B-36s x 72 1,000 lb bombs = 2,160 bombs.
Minimum safe distance for the M117 750 lb Hi Drag bomb is 160m for protected troops, and 830m for unprotected troops. And we're dropping 1,000 lb bombs here. A tree also won't offer much protection from fragments from the bombs.
2,160 bombs times 502.4 square meters (160m radius times 3.14) equals 1,085,184 square meters fragmented/blasted killed, or 1085 sq. km effectively churned over. That's pretty much enough damage to cover the target area of 54 square km 20 times over.
A much more important problem with TOAW3 is here:
Recently I tested the effect of 60 B-36s bombarding a 150 Rifle squad unit within a 5 kilometer hex. Time for turn was set to 6 hours. Now the damage done was in the range of 5-20% of the enemy. But I routinely lost upwards to a dozen bombers on the attack!
B-36s bombed from around 36,000 to 40,000+ feet. How is it that a rifle squad is going to be able to reach up to that altitude?
< Message edited by RyanCrierie -- 7/6/2006 1:09:10 AM >